Theory Exercises

Alkanes are saturated hydrocarbons that contain only single bonds between carbon atoms. Their general formula is \(C_nH_{2n+2}\), where \(n\) is the number of carbon atoms.

Nomenclature of linear alkanes

For linear alkanes, the following prefixes are used according to the number of carbon atoms:

CarbonsPrefixNameFormula
1Met-MethaneCH₄
2Et-EthaneC₂H₆
3Prop-PropaneC₃H₈
4But-ButaneC₄H₁₀
5Pent-PentaneC₅H₁₂
6Hex-HexaneC₆H₁₄
7Hept-HeptaneC₇H₁₆
8Oct-OctaneC₈H₁₈
9Non-NonaneC₉H₂₀
10Dec-DecaneC₁₀H₂₂

Nomenclature of branched alkanes

To name branched alkanes, follow these rules:

  1. Identify the main chain (the longest carbon chain).
  2. Number the main chain from the end nearest to the first branch.
  3. Identify and name the branches (alkyl radicals).
  4. Indicate the positions of the branches with numbers.
  5. If there are several identical radicals, use prefixes: di-, tri-, tetra-, etc.
  6. List the branches alphabetically (ignoring di-, tri-, etc. prefixes).

Main alkyl radicals

NameFormula
Methyl-CH₃
Ethyl-CH₂CH₃
Propyl-CH₂CH₂CH₃
Isopropyl-CH(CH₃)₂
Butyl-CH₂CH₂CH₂CH₃

Examples

2-methylbutane: 2-methylbutane

A butane with a methyl group at position 2, not at 3 because that would be a higher position.

3,3-dimethylhexane: 3,3-dimethylhexane

Main chain: hexane. With two methyl groups attached to the same carbon atom at position C3, forming a quaternary carbon.

2,3-dimethylbutane: 2,3-dimethylbutane

It does not matter whether you number from the left or the right because both ends are the same distance from the branches. The sum of the locants (2+3=5) is the same numbering from either end.

2,4,6-trimethylheptane: 2,4,6-trimethylheptane

If we number from the left, the methyls are at positions 2, 4, 6. If we number from the right, they are also at positions 2, 4, 6. In this case, we compare number by number: (2,4,6) = (2,4,6), so either numbering is correct.

3-ethyl-2-methylpentane:
3-ethyl-2-methylpentane
3-ethyl-2-methylpentane: If we number from the left, we have an ethyl at position 3 and a methyl at position 2. If we number from the right, we have an ethyl at position 3 and a methyl at position 4. The set (2,3) is lower than (3,4), so the first numbering is correct: 3-ethyl-2-methylpentane.