Energy is the capacity to produce changes, do work, or transfer heat.
- SI unit: joule (J)
- Other common units: kilocalorie (kcal) and kilowatt-hour (kWh) $1\,\text{kcal} = 4184\,\text{J}, \text{kWh} = 3.6 \times 10^6\,\text{J}$
Laws of Thermodynamics
1. Zeroth Law: If two systems are each in thermal equilibrium with a third one, they are in equilibrium with each other. 2. First Law (Energy conservation): Energy cannot be created or destroyed, only transformed. 3. Second Law: In real processes, energy tends to spread out and become less available for useful work (entropy increases).
Energy Sources
- Renewable: solar, wind, hydroelectric, geothermal, biomass.
- Non-renewable: coal, oil, natural gas, nuclear fuels.
Thermal Energy and Heat Transfer
Thermal energy depends on particle motion and amount of matter. Heat flows from higher to lower temperature.
Three transfer mechanisms
- Conduction: direct contact between particles.
- Convection: transfer through fluid motion (liquids and gases).
- Radiation: transfer by electromagnetic waves, no material medium required.
Everyday examples
- A tile floor feels colder than a carpet because tile conducts heat away from your skin faster.
- Air conditioners are usually high because cool air sinks.
- Heaters are usually low because warm air rises.
- Dark clothes absorb more solar radiation than light clothes.
Waves
Waves transfer energy, not matter.
- Transverse waves: vibration is perpendicular to propagation (example: light).
- Longitudinal waves: vibration is parallel to propagation (example: sound).
Main wave quantities
- Amplitude $A$ (m)
- Wavelength $\lambda$ (m)
- Frequency $f$ (Hz)
- Period $T$ (s)
- Wave speed $v$ (m/s) $v = \frac{\lambda}{T}$
Mechanical Energy
Mechanical energy is the sum of kinetic and potential energies:
For a system without friction:
Example 1 A $2\,\text{kg}$ ball is thrown downward from $20\,\text{m}$ with initial speed $10\,\text{m/s}$.
Using $g=9.8\,\text{m/s}^2$:
$mgh + \frac{1}{2}mv_0^2 = \frac{1}{2}mv^2$
$2\cdot 9.8\cdot 20 + \frac{1}{2}\cdot 2\cdot 10^2 = \frac{1}{2}\cdot 2\cdot v^2$
$392 + 100 = v^2 \Rightarrow v = \sqrt{492} \approx 22.18\,\text{m/s}$
Heat and Changes of State
Latent heat (phase change)
- $E_q$: heat energy (J)
- $m$: mass (kg)
- $L$: latent heat constant (J/kg)
Specific heat (temperature change)
- $c$: specific heat capacity (J/kg K)
- $\Delta T$: temperature change (K or degC)
Example 2 How much energy is needed to melt $2\,\text{kg}$ of ice at $0^\circ\text{C}$ and then heat the water to $80^\circ\text{C}$?
Given: $L_f=334000\,\text{J/kg}$ and $c=4184\,\text{J/(kg K)}$.
$E_q_{\text{melt}} = mL_f = 2\cdot 334000 = 668000\,\text{J}$
$E_q_{\text{heat}} = mc\Delta T = 2\cdot 4184\cdot (80-0) = 669440\,\text{J}$
$E_q_{\text{total}} = 668000 + 669440 = 1337440\,\text{J}$
Example 3 Find the final temperature when mixing $3\,\text{kg}$ of water at $10^\circ\text{C}$ with $10\,\text{kg}$ at $60^\circ\text{C}$.
Energy balance (no losses):
$m_1c(T_f-T_1) + m_2c(T_f-T_2)=0$
$3(T_f-10) + 10(T_f-60)=0$
$13T_f - 630 = 0 \Rightarrow T_f = \frac{630}{13} \approx 48.5^\circ\text{C}$